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Solve by the elimination method. 2x+3y=5, 4x+6y=10?
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Don't know how to solve by elimination. Note that the second equation is really the same as the first equation (divide both sides of the second equation by 2: 4x + 6y = 10 --> 2x + 3y = 5)... you see that really both equations are really identical.
[EDITED TO ADD]
Please understand that all the answerers telling you "x=1, y=1" are only right just for that one instance. What about x=2.5, y=0? Or x=10, y=-5? Any set of x and y values that fall on the line that goes through the points (0, 5/3) and (5/2, 0) are going to be solutions to your equations.
OK pretty simple.. First i would multiply your first equation by 2. which would give us 4x+6y=10. you are allowed to do this because you are multiplying both the left and right side so it is still equal. Now you see that the 2 equations are the same. This means there is no solution. (â ). so even if u tried to go on and do the elimination method:
4x-6y=10
-
4x-6y=10
________
0
you end up with zero. if this was to be the equation of 2 lines then the 2 lines would be the same. Good Luck =D
2x+3y=5 ----> multiply by -2
4x+6y=10 -> keep the same
-4x-6y=-10 -> add to
4x=6y=10 -> this
0=0
the equations are the same but the second one is doubled
2x+3y=5
x= 1 y= 1
2(1)+3(1)= 5
2+3=5
4x+6y=10
x=1 y=1
4(1)+6(1)=10
4+6=10
X and Y are both 1 for each equation
x=1 y=1
is it not obvious