Solve for "n"
4n+10n=28
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The question asks us to solve for n in the equation 4n + 10n = 28.
I begin by adding like terms:
4n + 10n = 28
14n = 28
Divide each side by 14 to get the true value of n:
[tex]\sf{n=2}[/tex]
Answer:-
Hence, the true value of n is 2.