Solve the inequality 3(x + 2)² ≥ −2(2x−23)+1
halp sumasabog na ang utak ko tnx
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Solve the inequality 3(x + 2)² ≥ −2(2x−23)+1
halp sumasabog na ang utak ko tnx
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3(x + 2)² ≥ - 2(2x - 23) + 1
(3x + 2)² ≥ - 2(2x + 23) + 1
9x² + 12x + 4 ≥ - 2(2x + 23) + 1
9x² + 12x + 4 ≥ - (4x + 46) + 1
A = 9x² + 12x + 4 ≥ - 4x + 47
Answer:
1. the parabola opens up or to the right
2. When 0">a>0, the parabola is located above the x-axis.
3. graph of y = x2, the point (0, 0) is called the vertex.
4.
5.vertex is the lowest point on the graph called the minimum, or min. When the parabola opens down, the vertex is highest point on the graph called the maximum, or max.
1. Yes
2. Negative because it goes downward
3 the vertex type is minimum because it goes to the low point
Step-by-step explanation:
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