Solve!
1. Completing the square:
6x²+5x=6
2. Quadratic Formula:
x²+3x+6=0
3. Use the discriminant to determine the number of real solutions of each equivalent quadratic equation.
a. x²+2x+3=0
b. 2x²-3x=4
4. Solve the inequality:
x²+x-6>0
5. Solve the given systems of equations:
x-y=2
x²-y=0
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Answer:
(1.)
6x^2 +5x =6
x^2 + 5/6x=1
x^2+ 5/6x+(5/12)^2 =1 +(5/12)^2
(x+5/12)^2 = 169/144
x= -3/2
x=2/3
(2.)
x^2+3x+6=0
x= -3 +/3^2-4x1x6
2x1
x= -3+/-15
2
X€ℝ *undefined
(4.)
x^2+x-6>0
x^2+x-6=0
(x+3)(x-2)=0
x+3=0| x-2=0
x=-3 | x=2
(-3,2)
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