special product pong lesson ito
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36. Find the product of (x - 2)(x + 2)(x² - 4).
37. Simplify (x - y)(x + y) - (x - y)²
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36.
• (x - 2)(x + 2)(x² - 4)
» (x² - 4)(x² - 4)
» x⁴ - 8x² + 16
Therefore, the answer in number 36 is:
x⁴ - 8x² + 16
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37.
• (x - y)(x + y) - (x - y)²
» (x² - y²) - (x² - 2xy + y²)
» -2y² + 2xy
Therefore, the answer in number 37 is:
-2y² + 2xy
36. x⁴ - 8x² + 16
37. -2y² + 2xy
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