a ball is thrown horizontally from the window of a multi storey building with a velocity of 5m/s.The ball falls 3.5m away from the building.
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a ball is thrown horizontally from the window of a multi storey building with a velocity of 5m/s.The ball falls 3.5m away from the building.
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Answer:
To solve this problem, we can use the equations of motion to determine the time of flight and the height of the building. Let's assume the acceleration due to gravity is approximately 9.8 m/s².
First, we need to find the time of flight. Since the ball is thrown horizontally, its initial vertical velocity is 0 m/s.
Using the equation for horizontal motion:
distance = velocity × time,
where distance is the horizontal distance traveled by the ball.
Given:
velocity = 5 m/s
distance = 3.5 m
Rearranging the equation:
time = distance / velocity
Substituting the values:
time = 3.5 m / 5 m/s
time ≈ 0.7 seconds
Now that we know the time of flight, we can determine the height of the building using the equation for vertical motion:
height = initial vertical velocity × time + (1/2) × acceleration due to gravity × time²
Since the initial vertical velocity is 0 m/s, the equation simplifies to:
height = (1/2) × acceleration due to gravity × time²
Substituting the values:
height = (1/2) × 9.8 m/s² × (0.7 s)²
height ≈ 2.43 meters
Therefore, the height of the building is approximately 2.43 meters.
Explanation:
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