Suppose that in a bag there are eight blue crayons, six yellow crayons, and five red crayons. What is the probability that on the first draw you will get a yellow crayon and on the second draw you will get a blue crayon assuming that the yellow crayon drawn was put back in the bag before drawing the blue crayon?
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Answer:
The probability of drawing a yellow crayon on the first draw and a blue crayon on the second draw, assuming that the yellow crayon drawn was put back in the bag, is 0.168 or approximately 16.8%.
Step-by-step explanation:
The probability of drawing a yellow crayon on the first draw is 6/19, since there are 6 yellow crayons out of a total of 19 crayons in the bag.
Since the yellow crayon is put back in the bag before drawing the blue crayon, the probability of drawing a blue crayon on the second draw is also 8/19, since there are still 8 blue crayons out of a total of 19 crayons in the bag.
To find the probability of both events happening, we can multiply their probabilities:
P(yellow and blue) = P(yellow) x P(blue|yellow)
= (6/19) x (8/19)
= 0.168