sw # 1.8 A. 1. 15 + 17 = 2. 38+ (-15) = 3. 3 + (-3) 4. 6 +7= 5. 4+ (-12) = 6. 8+ (-17)= 7. -13 +9= 8. -19 +(-7)= 9. -1+2+(-3)= 10.-17 + (-5) + (-12)
B. 1. A monkey sits on limb 25 feet above the ground. He swings up 10 feet climbs up 6 feet more and jumps down 13 feet. How far off the ground is the monkey now?
Share
Answer:
A. Let's solve the arithmetic problems one by one:
1. 15 + 17 = 32
2. 38 + (-15) = 23
3. 3 + (-3) = 0
4. 6 + 7 = 13
5. 4 + (-12) = -8
6. 8 + (-17) = -9
7. -13 + 9 = -4
8. -19 + (-7) = -26
9. -1 + 2 + (-3) = -2
10. -17 + (-5) + (-12) = -34
B. To find out how far off the ground the monkey is now, we can calculate the net distance covered by the monkey in both upwards and downwards directions from its initial position of 25 feet above the ground:
Upwards distance: 10 feet (swinging up) + 6 feet (climbing up) = 16 feet
Downwards distance: 13 feet (jumping down)
Net distance = Upwards distance - Downwards distance
Net distance = 16 feet - 13 feet
Net distance = 3 feet
Therefore, the monkey is now 3 feet off the ground.