(2×+3)
[tex]2 \times +{3})^{3} [/tex]
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(2×+3)
[tex]2 \times +{3})^{3} [/tex]
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• Problem:
Expand (2x+3)³.
• Lesson:
✓Cube of a Binomial.
• Solution:
✓Suppose a is the first term while b is the last or the second term.
The process will look like this one.
Let's solve.
• Answer:
The expanded form of (2x+3)³ is 8x³+36x²+54x+27.