Find x + y.
[tex]m + \frac{1}{m} = 3, x = m^2 + \frac{1}{m^2} , y = m^3 - \frac{1}{m^3}[/tex]
Share
Find x + y.
[tex]m + \frac{1}{m} = 3, x = m^2 + \frac{1}{m^2} , y = m^3 - \frac{1}{m^3}[/tex]
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Problem 1.4 Factor (a+2b−3c)3+(b+2c−3a)3+(c+2a−3b)3.
Solution Observe that (a+2b−3c)+(b+2c−3a)+(c+2a−3b)=0. Because x+y+z=0 implies x 3+y 3+z 3=3xyz, we obtain
(a+2b−3c)3+(b+2c−3a)3+(c+2a−3b)3=3(a+2b−3c)(b+2c−3a)(c+