Sample Problem 2
What is the potential energy of a 0.2 kg ball lifted to a height of 5.0 m above the ground?
Given:
m = 0.2 kg
h = 5.0 m
Find: [tex]PE_{g}[/tex]
Solution: [tex]PE_{g}[/tex] = mgh
= (0.2 kg)(9.8 m/[tex]s^{2}[/tex])(5.0 m)
= 9.8 Nm or 9.8 J
Question: Where did 9.8 m/[tex]s^{2}[/tex] come from?
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Answer:
constant gravity pull force I think