subject : General Mathematics
senior high school
solving rational equation : solve for x
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[tex]( \frac{1}{24x {}^{2} } = \frac{1}{12x {}^{2} } - \frac{1}{x} ) 24x {}^{2} \\ \ \\ \frac{24x {}^{2} }{24x {}^{2} } = \frac{24x {}^{2} }{12x {}^{2} } - \frac{24x {}^{2} }{x} \\ \\ 1 = 2 - 24x \\ 1 - 2 = 24x \\ \frac{ - 1}{24} = \frac{24x}{24} \\ \\ \frac{ - 1}{24} =x \\ \\ the \: answer \: is \: \\x = \binom{ - 1}{24} [/tex]
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Verified answer
Answer:
[tex]\mathrm{1.\:x = \frac{1}{24} }[/tex]
[tex]\mathrm{2.\:x = \frac{5}{48} }[/tex]
3. x = ±5
4. x = 4
5. x = 0
[tex]\mathrm{6.\: x = -\frac{44}{5} }[/tex]
[tex]\mathrm{7.\: x = \frac{35}{6} }[/tex]
Step-by-step explanation: