the 10th and 12th terms of an arithmetic sequence are 11 and 14, respectively.
a. WHAT IS D?
B. WHAT IS A1?
C. WHAT US A134?
D. HOW MANY TERMS ARE NEGATIVE?
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the 10th and 12th terms of an arithmetic sequence are 11 and 14, respectively.
a. WHAT IS D?
B. WHAT IS A1?
C. WHAT US A134?
D. HOW MANY TERMS ARE NEGATIVE?
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Answer:
a. 3
b-c. (refer to the explanation B-C)
d. (count the negative terms on explanation B-C)
Step-by-step explanation:
A.
d= a2-a1
14-11
= 3
B-C
A11= A12-3
=14-3
=11
A10= A11-3
=11-3
=8
A9= A10-3
=8-3
=5
A8= a9-3
5-3
2
A7= a8-3
2-3
-1
a6= a7-3
-1-3
-4
a5= a6-3
-4-3
-7
a4= a5-3
-7-3
-10
a3= a4-3
-10-3
-13
a2= a3-3
-13-3
-16
a1= a2-3
-16-3
-19
D. count the negative terms in B-C
Answer:
d=3/2
a1= -5/2
a134=394/2
2 -5/2 and -1
Step-by-step explanation:
14-11=3
3/2
d=3/2
14=a1 + (12-1)3/2
14=a1+(11)3/2
14=a1+33/2
14 - 33/2=a1
a1= -5/2
a134= -5/2+(134-1)3/2
a134= -5/2+(133)3/2
a134= -5/2+399/2
a134= 394/2
-5/2+3/2= -2/2 or -1
-1+3/2=1