The area of a rectangle is y^2 + 3y - 10. If the has a side length of 2y-4 then what is the width in terms of x?
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The area of a rectangle is y^2 + 3y - 10. If the has a side length of 2y-4 then what is the width in terms of x?
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Answer:
x= 1/2(y+5)
Step-by-step explanation:
y^2 + 3y- 10
= (y+5) (y-2)
=1/2 (y+5) (2y-4) { Factorization}
So ,X = 1/2 (y+5)