The first four term of a sequence are 28, 33, 38, 43.
Find the next three terms.
Find the 20th term.
Find the 51st term.
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The first four term of a sequence are 28, 33, 38, 43.
Find the next three terms.
Find the 20th term.
Find the 51st term.
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Answer:
20th term= 123
51st Term= 278
Step-by-step explanation:
Using the method of arithmetic sequence A(n)= a + d(n-1)
Which is a= The first term
d= common ratio
n= Number of term
On the given sequence: 28, 33, 38, 43.
The first term is 28
Common ratio is 5 (You add a number 5 in everytime you move a term consecutively''
Finding the 20th term
Using the formula of Arithmetic Sequence A(n)= a + d(n-1)
Substituting the given numbers,
A(20)= 28 + 5(20-1)
= 28 + 5(19)
= 28 + 95
= 123 (20th term)
Finding the 51st term
A(51)= 28 + 5(51-1)
= 28 + 5(50)
= 28 + 250
= 278