The length of a rectangel is 5cm greater than it's width.it's diagonal is 25cm.find the dimension.
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The length of a rectangel is 5cm greater than it's width.it's diagonal is 25cm.find the dimension.
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L = 20
W = 15
A = 1250
Step-by-step explanation:
Given:
L = (w+5)
w = w
hypotenuse = 25
Formula:
Pythagorean theorem
Find the width:
( w + 5 )² + w² = 25²
w² + 10w + 25 + w² = 625
2w² + 10w + 25 = 625
2w² + 10w + 25 - 625 = 625 - 625
2w² + 10w - 600 = 0
w² + 5w − 300 = 0
(w − 15 )( w + 20 ) = 0
w − 15 = 0 or w + 20 = 0
w = 15 or w = −20
note: -20 is not answer because it's negative, so the width is 15
Finding the area:
( w + 5 )² + w² = 25²
( 15 + 5 )² + 15² = 625
( 20 )² + 225 = 625
400 + 255 = 625
625 = 625 True, this is actually half the area of the
rectangle, so
multiply by 2 to get a whole area of the
rectangle.
finding the dimensions:
625 x 2 = A
1250 = A The area of the rectangle is 1250m²
L = (w + 5)
L = (15 + 5)
L = 20
W = w
W = 15
Answer:
width = 15 cm
length = 20 cm