the length of a rectangle is 2 feet less than 4 times the width. find the dimensions if the area is 132 ft2
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the length of a rectangle is 2 feet less than 4 times the width. find the dimensions if the area is 132 ft2
the length of a rectangle is 2 feet less than 4 times the width. find the dimensions if the area is 132 ft2
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Step-by-step explanation:
GIVEN:
Area = A = 132 ft²
Width = W
Length = L = 2 feet less than 4 times the width
L = 4W - w
FORMULA FOR AREA OF A RECTANGLE:
L × w = A
(4w -2)(w) = 132
4w² -2w = 132
4(w² - (2/4)w) = 132
4(w² - (2/4)w)/4 = 132/4
w² - (2/4)w = 33
w² - (1/2)w + 1/16 = 33 + 1/16
(w - 1/4)² = 529/16
√(w - 1/4)² = ±√(529/16)
w - 1/4 = ±23/4
ROOT 1:
w - 1/4 = 23/4
w - 1/4 + 1/4 = 23/4 + 1/4
w = 6 ft
ROOT 2:
w - 1/4 = -23/4
w - 1/4 + 1/4 = -23/4 + 1/4
w = -11/2 ft
NOTE: Since we are talking about dimension, neglect the negative root. Because there is no such thing as negative length and width.
L × w = A
(L × w)/w = A/w
L = A/w
L = 132 ft²/6 ft
L = 22 ft
The length of the rectangle is 22 ft while its width is 6 ft.