the length of the rectangle is 6x^2 - 5x + 4 and the width is 7x + 4, what is the perimeter of the rectangle?
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the length of the rectangle is 6x^2 - 5x + 4 and the width is 7x + 4, what is the perimeter of the rectangle?
nonsense +report
really needed
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QUESTIONS:
The length of the rectangle is 6x² - 5x + 4 and the width is 7x + 4, what is the perimeter of the rectangle?
ANSWER:
EXPLANATION:
Perimeter(P) of a rectangle is: P = 2(l + w). This means in this problem, we will need to add polynomial expressions and then multiply the sum by two. To add polynomials combine by adding the coefficients of similar terms.
SOLUTION:
-5x and 7x are similar terms, because they are both linear (x) terms, -5 + 7 + 2. -5x + 7x = 2x.
4 and 4 are similar terms, because they are both constant terms (no x involved at all), 4 + 4 = 8.
This makes l + w = (6x² - 5x + 4) + ( 7x + 4) = 6x² - 2x + 8. Now multiply by two, this is accomplished by distributing the multiplication of 2 to each of the coefficients. 2 x 6 = 12, 2 x 2 = 4, and 2 x 8 = 16
= 12 x² + 4x + 16 perimeter of rectangle
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