the product of the ages of his father and his son is 576.if the father is 18 years younger than 5 times his son,how old is each?
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the product of the ages of his father and his son is 576.if the father is 18 years younger than 5 times his son,how old is each?
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Answer:The problem is wrong it should be,The product of the age of a father and his son is 576.If the Father is 12 years younger than 5 times his son.So that we came from the answer 12 for the age of the son and 48 for the Father's age.
Step-by-step explanation:
Let s represent the age if the son and Let F represent the age if the father
s = son's age
5s-12 = father age
s (5 s -12) = 576
5s²-12s = 576
5s²-12s-576 = 0
(5s+48) (s-12) = 0
5s+48 =0 s-12 = 0
s=-48/5 s=12
Only positive integers are allowed so we only use 12 as the Age of the son
Age of the Father
F=5s-12
F=5(12)-12
F=60-12
F=48
So,48 is the value of Father's Age
Final Answers
s=12
F=48
Sana makatulong