The product of two consecutive integers is 90 less than twice the square of next larger integer. Find the smaller integer.
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The product of two consecutive integers is 90 less than twice the square of next larger integer. Find the smaller integer.
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Answer:
8 is the answer
Step-by-step explanation:
Answer:
ans. is 8
Step-by-step explanation:
Let: x = the first integer
x + 1 = second integer or next lager integer
x(x + 1) = 2 (x + 1)² - 90
x² + x = 2(x² + 2x + 1) - 90
x² + x = 2x² + 4x + 2 - 90
x² + 3x - 88 = 0
(x + 11) (x–8) = 0
x = 8
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