the sum of the roots of the quadratic equation is 51. If one of the roots is 7, how would you determine the equation?Write the equation
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the sum of the roots of the quadratic equation is 51. If one of the roots is 7, how would you determine the equation?Write the
Answer:
Answer:
x²-51x+308=0
Step-by-step explanation:
let f be the 2nd root
1st root + 2nd root = sum of roots
7 + f = 51
f = 44
let the quadratic equation be x² + b/a x + c/a=0
we all know that sum of roots = -b/a so:
-b/a = 51
-b/a ÷ (-1) = 51 / (-1)
b/a = -51
substituting:
x²-51x + c/a=0
remember that c/a represents the product of roots. to find their product, simply multiply the roots
c/a = 44 × 7 = 308
substituting and therefore
x²-51x+308=0