The towers supporting the cable of a suspension bridge are 1200m apart and 170m above the bridge it supports. Suppose the cable hangs, following the shape of a parabola, with its lowest point 20m above the bridge. Find the vertex of the parabola.
A.Vertex (0, 170)
B.Vertex (0, 20)
C.Vertex(0, 150)
D.Vertex (20, 170)
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Answer:
verticalparabolaequation.
(x−h)
2
=4p(y−k)
center(h,k)=(0,20)
attower(x,y)=(600,170)
substitutegivenvalues.
(600−0)
2
=4p(170−20)
600
2
=4p(150)
p=
600
600
2
=600
solveforheightat120mawayfromtower
x=600−120=480
y=?
(480−0)
2
=4(600)(y−20)
480
2
=2400y−48000
y=
2400
480
2
+48000
y=116m
Step-by-step explanation:
Pinakamalapit po ang B. 0,20
hope tama po (。◕‿◕。) if sakaling wrong po please no judgement po