the width of rectangular lot is 3 meters less than its length if the area of the lot is at most 130 square meters, what could be the dimension of the lot
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the width of rectangular lot is 3 meters less than its length if the area of the lot is at most 130 square meters, what could
Step-by-step explanation:
9 meters by 6 meters.
Step-by-step explanation:
First, translate the word problem into an equation by using variables.
Let x be the length. If x is the length, then the width is x - 3. The area of the rectangular lot is mentioned to be 54.
By applying the formula for the area of a rectangle,
a = 54, l = x, w = x - 3. So, we substitute these quantities into the formula.
Distribute x to the parenthesis.
Rewrite the quadratic equation into its standard form.
Factor the left hand side.
Equate each factor to 0.
Then, solve for x.
Next, rule out all extraneous solutions. Here, we rule out the possibility that x = -6, since measurements cannot be negative.
Hence, the value of x is 9.
Now, substitute 9 for the measurements of the length and the width.
If the length is x, then the length measures 9 meters.
If the width is x - 3, then the width measures 6 meters.
Therefore, the dimensions of the rectangular lot is 9 meters by 6 meters.