there were an urn and it has, 5 red balls, 3 yellow balls and 2 blue balls. How many possible outcomes if 4 of them will randomly and getting blue balls. Tabulate your answer with a sample space, R stand fo Red, B for blue, Y for yellow.
please po paki answer need napo agad asap. Thank you so much po
Share
Answer:
The probability of drawing a red ball first is p(R1)=310, and the probability of drawing a yellow ball second after a red ball is p(Y2|R1)=29.
The probability of drawing a yellow ball first is p(Y1)=210, and the probability of drawing a red ball second after a yellow ball is p(R2|Y1)=39.
Finally, the probability of drawing a red and yellow ball is:
p(R,Y)=p(R1∩Y2)+p(Y1∩R2)
=p(R1)p(Y2|R1)+p(Y1)p(R2|Y1)
=31029+21039
=215