U is the set of all days of the week . A is the set of all school days. B is the set of no school days and C is the set of days beggining with T
Find:
a. aub c. buc
b anc d. bna
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U is the set of all days of the week . A is the set of all school days. B is the set of no school days and C is the set of days beggining with T
Find:
a. aub c. buc
b anc d. bna
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Answer:
A. aub = {Mon, Tues, Wed, Thurs, Fri, Sat, Sun}
B. anc = {Tue, Thurs}
C. buc = {Tue, Thurs, Sat, Sun}
D. bna = {0} or null
Given:
A is set of all school days (Weekdays)
B is set of no school days (Weekends)
C is set of days beginning with T (Tue, Thurs)
Step-by-step explanation:
A. aub
Union means what's found in either sets
So aub = {Mon, Tues, Wed, Thurs, Fri, Sat, Sun}
B. anc
Intersection means whats common in both sets
so anc = {Tue, Thurs}
C. buc = {Tue, Thurs, Sat, Sun}
D. bna = {0} or null meaning there is nothing in common with sets b and a