What are the coordinates of the center of a circle whose equation is (x - 1)2 + (y + 3)2} = 9?
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What are the coordinates of the center of a circle whose equation is (x - 1)2 + (y + 3)2} = 9?
What are the coordinates of the center of a circle whose equation is (x - 1)2 + (y + 3)2} = 9?
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Answer:
the center is (1, -3) and the radius is 3
Explanation:
in the form
(x−
x0
)
2
+
(
y
−
y
0
)
2
=
r
2
you can see that the center is
(
x
0
,
y
0
)
and the radius is r
so the center is (1, -3) and the radius is 3