what are the roots of the quadratic equation x squared plus x minus 56 = 0
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what are the roots of the quadratic equation x squared plus x minus 56 = 0
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Answer:
first root = -8
second root = 7
Step-by-step explanation:
x²+x-56
1st: use factoring in solving
2nd: to factor the equation: find the factors of 56 that when you add will result to 1 (56 is the value of A times C coefficient; 1 is the value of B coefficient)
3rd: write it as (x+8)(x-7)
4th: equate the factors to zero
and the result is -8 and 7
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