What is factor of x^3 + 6
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==> x^3 - x - 6 = 0
==> 8 - 2 -6 = 0
Then x= 2 is a root for the equation.
==> (x-2) is a factor.
Now we will divide by (x-2) to find other factors.
==> (x^3 - x - 6) = (x-2) (x^2 + 2x+ 3)
Now sine delta = (4-4*3) = 4-12 = -8 < 0
Then there are no Real roots foe the quadratic equation.