What is the concentration of a CaBr2 solution if 125.00 g of solute was dissolved in enough water to form 250. ml of solution?
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What is the concentration of a CaBr2 solution if 125.00 g of solute was dissolved in enough water to form 250.
Answer:
Concentration can be defined in terms of molarity. The molarity has been the moles of solute present in a liter of solution.
Moles of \rm CaBr_2CaBr
2
can be calculated as:
Moles = \rm \dfrac{weight}{molecular\;weight}
molecularweight
weight
Molecular weight of \rm CaBr_2CaBr
2
= 199.89 g/mol
Moles of \rm CaBr_2CaBr
2
= \rm \dfrac{125}{199.89}
199.89
125
Moles of \rm CaBr_2CaBr
2
= 0.625 mol.
Volume of solution = 250 ml
1000 ml = 1 L
250 ml = 0.25 L
Molarity = \rm \dfrac{moles}{Volume\;(L)}
Volume(L)
moles
Molarity = \rm \dfrac{0.625}{0.25}
0.25
0.625
Molarity = 2.50 M.
The concentration of 125 grams, 250 ml \rm CaBr_2CaBr
2
solution has been 2.50 M.
Explanation:
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