what is the density of argon in a light bulb at 1.2 atm and 24 degree celcius
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what is the density of argon in a light bulb at 1.2 atm and 24 degree celcius
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Answer:
d = 2.0 g/L
Explanation:
Converting °C to K.
T = 24 °C + 273
T = 297 K
Calculating the density of argon gas.
d = P • MW / RT
d = 1.2 atm • 39.9 g/mol / (0.0821 L•atm/mol•K)(297 K)
d = 2.0 g/L
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