what is the first term of a sequence whose 6th term is 128 and whose common ratio is 2?
A.4
B.16
C.24
D.32
Share
what is the first term of a sequence whose 6th term is 128 and whose common ratio is 2?
A.4
B.16
C.24
D.32
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
a1=4
Step-by-step explanation:
Given:a6=128 ; r=2
Formula:an=a1(r)^n-1
Solution:a6=a1(2)^2-1
128=a1(2)^5
128=a1(32)
over | over
32 32 (Cancel both 32 on the right
side)
4=a1