what is the mass percentage of a solution made by dissolving 10 g soda in 100 g of water
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what is the mass percentage of a solution made by dissolving 10 g soda in 100 g of water
what is the mass percentage of a solution made by dissolving 10 g soda in 100 g of water
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Answer:
Correct option is
A
2.5 m
Molality =
mass of solvent(kg)
number of moles of solute
and number of moles =
molar mass
mass
For NaOH, mass = 10g, molar mass = 40 g/mol
and water, mass = 100g = 0.1 kg
Thus, molality=
40×0.1
10
=2.5 m
Explanation:
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