What is the molality of a solution containing 7.78 g of urea [(NH₂)₂CO] in 203 g of water?
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What is the molality of a solution containing 7.78 g of urea [(NH₂)₂CO] in 203 g of water?
What is the molality of a solution containing 7.78 g of urea [(NH₂)₂CO] in 203 g of water?
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SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & mass_{\text{solute}} = \text{7.78 g} \\ & MM_{\text{solute}} = \text{60.055 g/mol} \\ & mass_{\text{solvent}} = \text{203 g = 0.203 kg} \end{aligned}[/tex]
Step 2: Calculate the number of moles of solute.
[tex]\begin{aligned} n_{\text{solute}} & = \frac{mass_{\text{solute}}}{MM_{\text{solute}}} \\ & = \frac{\text{7.78 g}}{\text{60.055 g/mol}} \\ & = \text{0.12955 mol} \end{aligned}[/tex]
Step 3: Calculate the molality of solution.
[tex]\begin{aligned} m & = \frac{n_{\text{solute}}}{mass_{\text{solvent}}} \\ & = \frac{\text{0.12955 mol}}{\text{0.203 kg}} \\ & = \text{0.638 mol/kg} \\ & = \boxed{0.638 \: m} \end{aligned}[/tex]
Hence, the molality of the solution is 0.638 m.
[tex]\\[/tex]
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