What is the osmotic pressure (in atm) of a 0.884 M urea solution at 16°C?
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What is the osmotic pressure (in atm) of a 0.884 M urea solution at 16°C?
What is the osmotic pressure (in atm) of a 0.884 M urea solution at 16°C?
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SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & M = 0.884 \: M = \text{0.884 mol/L} \\ & T = 16^{\circ}\text{C} = \text{289.15 K} \end{aligned}[/tex]
Step 2: Calculate the osmotic pressure of the solution.
[tex]\begin{aligned} \pi & = MRT \\ & = (\text{0.884 mol/L})\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{289.15 K}) \\ & = \boxed{\text{20.97 atm}} \end{aligned}[/tex]
Hence, the osmotic pressure is 20.97 atm.
[tex]\\[/tex]
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