what is the result when twice the square of 3x subtracted from the product of the square root of 16x² and thrice the number x?
a. 6x²
b. -6x²
c. 48x³ - 18x²
d. 30x²
e. -30x²
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what is the result when twice the square of 3x subtracted from the product of the square root of 16x² and thrice the number x?
a. 6x²
b. -6x²
c. 48x³ - 18x²
d. 30x²
e. -30x²
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Answer:
Let's break down the problem step by step.
The product of the square root of 16x² and thrice the number x is:
sqrt(16x²) x 3x = 4x x 3x = 12x²
Twice the square of 3x is:
2 x (3x)² = 2 x 9x² = 18x²
Therefore, the expression "twice the square of 3x subtracted from the product of the square root of 16x² and thrice the number x" is:
12x² - 18x² = -6x²
So the answer is (b) -6x².
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Step-by-step explanation:
The expression for the given problem is:
√(16x²) x 3x - 2(3x)²
Simplifying this expression, we get:
4x x 3x - 2(9x²)
12x² - 18x²
-6x²
Therefore, the answer is option (b) -6x².