When the original price of an item is increased by a certain rate the increased price is P3 100 when the original price is decreased by the same rate the decrease price is P1 900 what is the original price of this item?
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When the original price of an item is increased by a certain rate the increased price is P3 100 when the original price is decreased by the same rate the decrease price is P1 900 what is the original price of this item?
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➢O.P ( 1+r ) = P 3,100
➢O.P ( 1-r ) = P 1,900
➢31 ( 1+r ) = 19 ( 1 + r )
➢31 - 31r = 19 + 19r
➢31 - 19 = 31r + 19r
➢12= 50r
➢r = 12/50 = 0.24
➢Answer : P 2 500
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Answer:
Question:
When the original price of an item is increased by a certain rate the increased price is P3 100 when the original price is decreased by the same rate the decrease price is P1 900 what is the original price of this item?
\huge \rm{Answer : }Answer:
➢O.P ( 1+r ) = P 3,100
➢O.P ( 1-r ) = P 1,900
\small\rm{O.P = \frac{ \ P \: 3100}{(1 + r)} } \: \: \: \: \: \: \: \small\rm{O.P = \frac{ \ P \: 1 \: 900}{(1 + r)}}O.P=
(1+r)
P3100
O.P=
(1+r)
P1900
➢31 ( 1+r ) = 19 ( 1 + r )
➢31 - 31r = 19 + 19r
➢31 - 19 = 31r + 19r
➢12= 50r
➢r = 12/50 = 0.24
\small\rm{O.P = \frac{ \ P \: 3 \: 100}{(1 + r)}} \: = \: \small\rm{O.P = \frac{ \ P \: 3 \: 100}{(1 + 0.24)}} \: = \: \small\rm{O.P = \frac{ \ P \: 3 \: 100}{(1 + .24)}} = \: P \: 2 \: 500O.P=
(1+r)
P3100
=O.P=
(1+0.24)
P3100
=O.P=
(1+.24)
P3100
=P2500
➢Answer : P 2 500
\huge\red{\overline{ \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}
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