simplify the algebraic expression x-7/x²-11x+28
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Answer:
[tex]\frac{1}{x-4}[/tex]
Step-by-step explanation:
[tex]\frac{x-7}{x^{2}-11x+28 }\\=\frac{x-7}{x^{2} -7x-4x+28} \\=\frac{x-7}{(x^{2} -7x)-(4x-28)}\\=\frac{x-7}{x(x-7)-4(x-7)}\\=\frac{x-7}{(x-4)(x-7)}\\=\frac{1}{x-4}[/tex]
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