10. What is the remainder when n3 - 7 is divided by n +5?
A. 118
C. 132
B. -132
D. – 118
11. (2x3.5x2 + 3x + 7) + (x - 2)
C. 2x2 - x + 1
A. 2x3 . x2 + x + 9
B. 2x2 - X+1 + 9/x-2
D. 2x2 - 9x - 15 - 23/x-2
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10. What is the remainder when n3 - 7 is divided by n +5?
A. 118
C. 132
B. -132
D. – 118
11. (2x3.5x2 + 3x + 7) + (x - 2)
C. 2x2 - x + 1
A. 2x3 . x2 + x + 9
B. 2x2 - X+1 + 9/x-2
D. 2x2 - 9x - 15 - 23/x-2
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Answer:
B
If and are positive integers, there exist unique integers and , called the quotient and remainder, respectively, such that and .
For example, when 15 is divided by 6, the quotient is 2 and the remainder is 3 since .
Notice that means that remainder is a non-negative integer and always less than divisor.
This formula can also be written as
Answer:
B. -132
Step-by-step explanation:
Standard: n²–5n–132/n+5 +25
Quotient: n²–5n+25
Remainder: –132
Explanation:
Divide using long division:
"divisor": "n + 5"
"dividend": "n^{3} + 0 n^{2} + 0 n - 7"
"quotient": "n^{2} - 5 n + 25"
"remainder": "-132"
"sub_divs": ["val": "n^{2}"
"sub_exp": "n^{3} + 5 n^{2}"
"remainder": "- 5 n^{2} - 7"
"val": "- 5 n"
"sub_exp": "- 5 n^{2} - 25 n"
"remainder": "25 n - 7"
"val": "25"
"sub_exp": "25 n + 125"
"remainder": "-132"