x²-5x+10=0 pasagot with solution
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[tex]\LARGE\tt✏SOLUTION :[/tex]
[tex] \footnotesize \begin{array}{l}\texttt{To solve the quadratic equation }\\\tt{(x^2 - 5x + 10 = 0)}\\\texttt{, we can use the quadratic formula:}\\\\
\tt{x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}
\\ \\
\texttt{In this equation, }\\ \\ \tt{(a = 1), (b = -5), and (c = 10).}\\\\
\texttt{Plugging in these values, we have:}\\\\
\tt{x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(1)(10)}}{2(1)}}\\\\
\texttt{Simplifying further:}\\\\
\tt{x = \frac{5 \pm \sqrt{25 - 40}}{2}}\\
\tt{x = \frac{5 \pm \sqrt{-15}}{2}}
\\ \\
\texttt{The square root of a negative number indicates} \\\texttt{no real solutions. Therefore, the equation }\\ \\ \boxed{\tt(x^2 - 5x + 10 = 0) } \\ \\ \boxed{ \texttt{{ has no real solutions.}}} \end{array}
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