x2 Example 5. Evaluate Getsiz #s). x3 +5x22x+1 Since the denominator is not o when evaluated atx -2, we can apply the previous theorem. (4+5+8+2x+ 7) + (-23 51-53-271-27+ () (-2)3 + 5(-2)2 - 2(-2) + 1 3 - 1 4 17
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x2 Example 5. Evaluate Getsiz #s). x3 +5x22x+1 Since the denominator is not o when evaluated atx -2, we can apply the previous theorem. (4+5+8+2x+ 7) + (-23 51-53-271-27+ () (-2)3 + 5(-2)2 - 2(-2) + 1 3 - 1 4 17
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