(x+5)^2+(x-2)^2=37?
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SOLUTION⤵️
expanding the binomials
(x+5)²= (x+5)(x+5) = x²+5x+5x+25 = x²+10x+25
(x-2)²= (x-2)(x-2) = x²-2x-2x+4 = x²-4x+4
adding thesame terms
= x²+10x+25 + x²-4x+4
= x²+x²+10x-4x+25+4
= 2x²+6x+29
ANSWER⤵️
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