y=-2x2-2
Vertex:
opening of the point:
Vertex is a___point:
Equation of the axis of symmetry:
Domain:
Range:
pa sagot po again
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y=-2x2-2
Vertex:
opening of the point:
Vertex is a___point:
Equation of the axis of symmetry:
Domain:
Range:
pa sagot po again
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Verified answer
QUADRATIC FUNCTION
Remember:
Given : y = -2x²-2
Solution:
We will transform the standard form to vertex form
y = ax²+bx + c to y = a(x-h)²+k
Where h = 0 , k = -2
Since the value of a is negative , then it opens downward
EAS: y = k
y = -2
Range: y ≥ k
y ≥ -2
ANSWER
Vertex is at (h,k)
opening of the point: downward
Vertex is at (0,-2)
Equation of axis of symmetry: y = -2
Domain: All real numbers
Range: y ≤ -2
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