y = x3 + 3x2 - 4x - 12
Group the terms ( ax3 +bx) ( x + d)
Factor x2 out of the first group of terms.
Factor the constants out of both groups.
Add the two terms by adding the coefficients.
This can be further factored as a difference of squares,
So, the factored form is
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Solution:
or (x+2) (x-2) (x+3)