Suppose w varies directly as x and inversely as the square of y.When x = 8 when y = 4 and w = 18,what is the value of w if x = 4 and y = 6? (Hint: the equation is w = kx/y²)
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Suppose w varies directly as x and inversely as the square of y.When x = 8 when y = 4 and w = 18,what is the value of w if x = 4 and y = 6? (Hint: the equation is w = kx/y²)
Pls answer this respectfully
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Answer:
w = kx/y²
18 = k(8)/(4)²
18 = 8k/16
18 = 8k/16 ÷ 8/8
18 = k/2
18 × 2 = k/2 × 2
36 = k
w = 36(4)/(6)²
= 144/36
= 144/36 ÷ 36/36
w = 4
w =x
y²
w = k x
y²
w = k x 8
(4)²
k = 36
when x = 4;y = 6
w = K x X
y²
= 36 x 4
62
W = 4
Step-by-step explanation:
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